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Test your chess: Reitstein problem 136

May 9, 2014

Black to play and win

 

 

 

PJS Robbertse v A Haller 1967

 

Solution

 

Black's situation looks dire, and Reitstein says that he resigned in this position. But knowing that it is a problem (and I think that is key: it would be so easy to give up here in practice) the solution is simple: 1…Qd1, pinning the LPDO rook against the LPDO Qh5, and if 2 Kf2, 2…Bg3+ wins.

White's best is 2 Qe8+, playing for tricks. 2…Re8[] 3 Re8+ Kh7?? 4 g6 mate, so 3…Kf7[] when 4 Rge3 Qg4+ scoops up the pawns, when black wins, eventually, with Q+B and more pawns v RR+B and fewer pawns.

 

From → Chess

2 Comments
  1. Stewart Fishburne's avatar
    Stewart Fishburne permalink

    Either the last comment is correct (Q+B v 2R should read Q+B v 2R+B), or the WB on b2 shouldn’t be there

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